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Trapezoidal Approximation Calculator

Estimate a definite integral with the trapezoidal rule from a function or from a table of data with uneven spacing, with left, right and midpoint sums.

What do you want to work out?

Result

Integral≈ 2.75
Set-upn = 4 trapezoids, Δx = (2 − 0) ÷ 4 = 0.5
Riemann sumsleft sum 1.75 · right sum 3.75 · midpoint 2.625
Accuracy checkwith n = 8: 2.6875; the n = 4 result is about 0.0833333 too high
Worth knowingthe trapezoidal rule is the average of the left and right sums; it overestimates where f is concave up

How this was calculated

  1. Δx0.5
  2. Values0, 0.25, 1, 2.25, 4
  3. Trapezoidal ruleΔx × (f0/2 + f1 + … + f(n−1) + fn/2) = 2.75

About the Trapezoidal Approximation Calculator

The trapezoidal rule estimates the area under a curve by splitting it into strips and treating each strip as a trapezoid whose top joins two neighbouring points with a straight line. It is one of the first numerical integration methods taught in calculus, it works directly with measured data, and it is the basis for many of the area questions on AP Calculus exams.

This trapezoidal approximation calculator works in two ways. From a function, it splits the interval into equal strips and also reports the left, right and midpoint Riemann sums for comparison, with an accuracy check. From a data table, it uses the x and y values you supply, with equal or unequal widths, which is how most real measurements arrive.

How to Use the Trapezoidal Approximation Calculator

Choose from a function or from a data table.

For a function, enter f(x), the lower limit a, the upper limit b and the number of trapezoids n.

For a table, enter the x values in increasing order and the matching y values, separated by commas.

The Formulas

  equal strips:   Δx = (b − a) / n
                  T = Δx × (f0/2 + f1 + f2 + … + f(n−1) + fn/2)
  any widths:     T = Σ (x(i+1) − xi) × (yi + y(i+1)) / 2
  left sum  L = Δx × (f0 + … + f(n−1))     right sum  R = Δx × (f1 + … + fn)
  T = (L + R) / 2

Step-by-Step Example: A Function

Estimate the integral of x² from 0 to 2 with n = 4. The exact value is 8/3 ≈ 2.6667.

  Δx = (2 − 0) / 4 = 0.5
  f:  0, 0.25, 1, 2.25, 4
  T  = 0.5 × (0/2 + 0.25 + 1 + 2.25 + 4/2) = 0.5 × 5.5 = 2.75
  left sum 1.75, right sum 3.75, midpoint 2.625

The trapezoidal estimate is 0.0833 above the true value because x² is concave up. The midpoint sum, 2.625, is 0.0417 below, about half the trapezoidal error and in the opposite direction, which is typical for smooth curves.

Step-by-Step Example: A Table With Unequal Widths

x = 0, 1, 3, 4, 7 and y = 2, 5, 7, 6, 3.

  [0, 1]  1 × (2 + 5) / 2 = 3.5
  [1, 3]  2 × (5 + 7) / 2 = 12
  [3, 4]  1 × (7 + 6) / 2 = 6.5
  [4, 7]  3 × (6 + 3) / 2 = 13.5
  total = 35.5,  average value = 35.5 / 7 ≈ 5.07

If y is a rate, such as litres per minute or metres per second, the total is the accumulated amount, such as litres or metres.

Trapezoids, Riemann Sums and Midpoints

Left and right Riemann sums use rectangles whose height comes from one end of each strip. For an increasing function, the left sum underestimates and the right sum overestimates. The trapezoidal rule is exactly their average, which cancels much of the error. The midpoint rule uses rectangles whose height comes from the centre of each strip and is usually about twice as accurate as the trapezoidal rule, with an error of the opposite sign.

Weighting the midpoint sum twice and the trapezoidal sum once, (2M + T)/3, gives Simpson's rule. For the x² example that is (2 × 2.625 + 2.75)/3 = 2.6667, the exact answer, because Simpson's rule is exact for quadratics.

Overestimates and Underestimates

The sign of the trapezoidal error depends on concavity. Where the graph curves upward, like x² or e^x, each straight top sits above the curve and the rule overestimates. Where it curves downward, like √x or sin(x) on 0 to π, it underestimates. Exam questions often ask you to justify whether an estimate is too high or too low; the second derivative, or the shape of the data, answers that.

Accuracy and Choosing n

The error of the trapezoidal rule shrinks with the square of the strip width. Doubling n roughly quarters the error. The calculator uses this to estimate the error: it compares the results for n and 2n and scales the difference by 4/3. For data tables you cannot add points, so the estimate cannot be refined; collect readings more often where the values change quickly.

Using the Rule in Exam Questions

AP Calculus free response questions often give a table of times and rates, such as the rate water flows into a tank, and ask for a trapezoidal estimate of the total amount over an interval. Write the sum with each width and average height, as in 1 × (2 + 5)/2, so the method is clear, and include units: if the rate is in litres per minute and the widths are in minutes, the total is in litres. A follow-up question may ask for the average rate, which is the total divided by the length of the interval.

Questions also ask whether an estimate is too high or too low. That can only be decided when the function is known to be concave up or concave down on the whole interval; with an unknown curve through table points, the honest answer is that it cannot be determined from the data alone.

Integrals That Are Not Areas

When the function dips below the x-axis, the trapezoidal rule treats those values as negative, just as the integral does. The result is then the net signed area, not the total area. To find the total area between a curve and the axis, integrate the absolute value, entering abs(f(x)) as the function, and use enough strips that the points where the curve crosses the axis are resolved.

Understanding Your Result

The headline gives the trapezoidal estimate of the integral.

The set-up line shows the number of trapezoids and the strip width, or the range and whether the widths are equal.

The Riemann sums line compares left, right and midpoint sums in function mode.

The accuracy check shows the result with twice as many trapezoids and whether your estimate is too high or too low.

The average value in table mode is the integral divided by the width of the interval.

When Should You Use This Calculator?

Use it for AP Calculus and A-level questions that give a table of values.

Use it to estimate totals from rate data, such as distance from speed or volume from flow.

Use it to compare the trapezoidal rule with Riemann sums for a function.

Common Mistakes

Halving every value. Only the first and last values are halved when the widths are equal.

Assuming equal widths. Check the x values; uneven spacing needs each trapezoid's own width.

Mismatched lists. Every x needs exactly one y.

Confusing concavity. Concave up overestimates; concave down underestimates.

Frequently Asked Questions

How do you use the trapezoidal rule?

Split the interval into n strips of width Δx, join the curve's values at each edge with straight lines and add the trapezoid areas: Δx times half the first and last values plus all the values in between.

How do I find a trapezoidal sum from a table?

Use each pair of neighbouring points as one trapezoid: width x(i+1) − xi times the average of the two y values. For x = 0, 1, 3, 4, 7 and y = 2, 5, 7, 6, 3 the total is 3.5 + 12 + 6.5 + 13.5 = 35.5.

Can the widths be unequal?

Yes, in table mode each trapezoid uses its own width, which is common in AP Calculus questions built from measured data. In function mode the strips are equal, set by the number of trapezoids n.

How does the trapezoidal rule relate to Riemann sums?

It is exactly the average of the left and right Riemann sums. For x² from 0 to 2 with n = 4, the left sum is 1.75 and the right is 3.75, so the trapezoidal estimate is 2.75.

Does the trapezoidal rule overestimate or underestimate?

Where the function is concave up the straight tops lie above the curve, so it overestimates; where it is concave down it underestimates. For x² the estimate of 2.75 is above the exact 8/3.

How accurate is the trapezoidal rule?

Its error shrinks with the square of the strip width, so doubling n cuts the error about fourfold. The calculator compares with 2n strips and scales the gap by 4/3 to estimate the error.

Formula and article last checked September 28, 2026. How we test these calculators.